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7x^2-60x-27=0
a = 7; b = -60; c = -27;
Δ = b2-4ac
Δ = -602-4·7·(-27)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-66}{2*7}=\frac{-6}{14} =-3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+66}{2*7}=\frac{126}{14} =9 $
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